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  • All right welcome back this is question eight of
  • ... first let's start off by finding the new bounds U of one would just be 330 minus 4 because
  • At there we go now that we have plug this in using unit circle we'll be able to know that all of these values will be this -
  • Right welcome back this is question eight I believe uh yes it is eight so we have this curve Ln of X over x^2 from
  • Q8 WeBWork 5.3

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Q8 WeBWorK 1.3 So 2 * Ln x * ... we know that we have three 9 minus Is it is simply oh well 2 n^ 2us

All right this is question eight we have this um definite integral from 0 to pi over

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